If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x^2)+2x-0.005=0
a = 2; b = 2; c = -0.005;
Δ = b2-4ac
Δ = 22-4·2·(-0.005)
Δ = 4.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{4.04}}{2*2}=\frac{-2-\sqrt{4.04}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{4.04}}{2*2}=\frac{-2+\sqrt{4.04}}{4} $
| –2y^2+6y=–2 | | -6.1=u/6+13.1 | | 90+x(2x-20)+(x+10)=360 | | 19=46-9x | | (-11/6+m=-2/9m= | | 24-6(2x-8)=-2(5x+10) | | -b+6b=-10 | | Y=-0.125+0.075x | | -21=-7(w+1 | | 4x+6=-6(x+9) | | 5(-2y+4)=60 | | 5x+x+6=6x+4+1 | | 2.1=-4.6n+13.4 | | 8x-(2x-8)=4(x+7) | | 3x-15+(5X-23)=90 | | Q=6m(T2-T1) | | (3x+16)=5x | | 6x-5=x+17 | | 2x+5+2x+7=180 | | A+b=120 | | 3n2–9n=0 | | x+10+79+x-1+2x=360 | | x+x89=180 | | 5x+55=113 | | X^2-x-(7/4)=0 | | 2x+52+88+x+2+x+10=540 | | X^2-x-(7/4)X=0 | | 3(m+6)=6(m-1+ | | X^2-x-(7/4)2=0 | | x+2+x-8+x+7+x-3+x+6+x-4=540 | | 3x(2x-7)=-5(2x-12) | | 5a=57 |